2y-3(4y-8)=(5+y)-10

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Solution for 2y-3(4y-8)=(5+y)-10 equation: 



2y-3(4y-8)=(5+y)-10

We move all terms to the left:

2y-3(4y-8)-((5+y)-10)=0

We add all the numbers together, and all the variables

2y-3(4y-8)-((y+5)-10)=0

We multiply parentheses

2y-12y-((y+5)-10)+24=0



We calculate terms in parentheses: -((y+5)-10), so:

(y+5)-10

We get rid of parentheses

y+5-10

We add all the numbers together, and all the variables

y-5

Back to the equation:

-(y-5)



We add all the numbers together, and all the variables

-10y-(y-5)+24=0

We get rid of parentheses

-10y-y+5+24=0

We add all the numbers together, and all the variables

-11y+29=0

We move all terms containing y to the left, all other terms to the right

-11y=-29

y=-29/-11

y=2+7/11

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