2y-3(5y-1)=-1-5(1-y)

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Solution for 2y-3(5y-1)=-1-5(1-y) equation: 



2y-3(5y-1)=-1-5(1-y)

We move all terms to the left:

2y-3(5y-1)-(-1-5(1-y))=0

We add all the numbers together, and all the variables

2y-3(5y-1)-(-1-5(-1y+1))=0

We multiply parentheses

2y-15y-(-1-5(-1y+1))+3=0



We calculate terms in parentheses: -(-1-5(-1y+1)), so:

-1-5(-1y+1)

determiningTheFunctionDomain
-5(-1y+1)-1

We multiply parentheses

5y-5-1

We add all the numbers together, and all the variables

5y-6

Back to the equation:

-(5y-6)



We add all the numbers together, and all the variables

-13y-(5y-6)+3=0

We get rid of parentheses

-13y-5y+6+3=0

We add all the numbers together, and all the variables

-18y+9=0

We move all terms containing y to the left, all other terms to the right

-18y=-9

y=-9/-18

y=1/2

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