2y-3(y+1)=(5y+3)+y

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Solution for 2y-3(y+1)=(5y+3)+y equation:


Simplifying
2y + -3(y + 1) = (5y + 3) + y

Reorder the terms:
2y + -3(1 + y) = (5y + 3) + y
2y + (1 * -3 + y * -3) = (5y + 3) + y
2y + (-3 + -3y) = (5y + 3) + y

Reorder the terms:
-3 + 2y + -3y = (5y + 3) + y

Combine like terms: 2y + -3y = -1y
-3 + -1y = (5y + 3) + y

Reorder the terms:
-3 + -1y = (3 + 5y) + y

Remove parenthesis around (3 + 5y)
-3 + -1y = 3 + 5y + y

Combine like terms: 5y + y = 6y
-3 + -1y = 3 + 6y

Solving
-3 + -1y = 3 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
-3 + -1y + -6y = 3 + 6y + -6y

Combine like terms: -1y + -6y = -7y
-3 + -7y = 3 + 6y + -6y

Combine like terms: 6y + -6y = 0
-3 + -7y = 3 + 0
-3 + -7y = 3

Add '3' to each side of the equation.
-3 + 3 + -7y = 3 + 3

Combine like terms: -3 + 3 = 0
0 + -7y = 3 + 3
-7y = 3 + 3

Combine like terms: 3 + 3 = 6
-7y = 6

Divide each side by '-7'.
y = -0.8571428571

Simplifying
y = -0.8571428571

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