2y-3(y+1)=-(6y+7)+y

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Solution for 2y-3(y+1)=-(6y+7)+y equation:



2y-3(y+1)=-(6y+7)+y
We move all terms to the left:
2y-3(y+1)-(-(6y+7)+y)=0
We multiply parentheses
2y-3y-(-(6y+7)+y)-3=0
We calculate terms in parentheses: -(-(6y+7)+y), so:
-(6y+7)+y
We add all the numbers together, and all the variables
y-(6y+7)
We get rid of parentheses
y-6y-7
We add all the numbers together, and all the variables
-5y-7
Back to the equation:
-(-5y-7)
We add all the numbers together, and all the variables
-1y-(-5y-7)-3=0
We get rid of parentheses
-1y+5y+7-3=0
We add all the numbers together, and all the variables
4y+4=0
We move all terms containing y to the left, all other terms to the right
4y=-4
y=-4/4
y=-1

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