2y-3(y+1)=-(6y+7)+y

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Solution for 2y-3(y+1)=-(6y+7)+y equation: 



2y-3(y+1)=-(6y+7)+y

We move all terms to the left:

2y-3(y+1)-(-(6y+7)+y)=0

We multiply parentheses

2y-3y-(-(6y+7)+y)-3=0



We calculate terms in parentheses: -(-(6y+7)+y), so:

-(6y+7)+y

We add all the numbers together, and all the variables

y-(6y+7)

We get rid of parentheses

y-6y-7

We add all the numbers together, and all the variables

-5y-7

Back to the equation:

-(-5y-7)



We add all the numbers together, and all the variables

-1y-(-5y-7)-3=0

We get rid of parentheses

-1y+5y+7-3=0

We add all the numbers together, and all the variables

4y+4=0

We move all terms containing y to the left, all other terms to the right

4y=-4

y=-4/4

y=-1

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