2y-3(y+9)=40

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Solution for 2y-3(y+9)=40 equation: 



2y-3(y+9)=40

We move all terms to the left:

2y-3(y+9)-(40)=0

We multiply parentheses

2y-3y-27-40=0

We add all the numbers together, and all the variables

-1y-67=0

We move all terms containing y to the left, all other terms to the right

-y=67

y=67/-1

y=-67

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