2y-3(y-4)=2(y-5)-11

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Solution for 2y-3(y-4)=2(y-5)-11 equation:


Simplifying
2y + -3(y + -4) = 2(y + -5) + -11

Reorder the terms:
2y + -3(-4 + y) = 2(y + -5) + -11
2y + (-4 * -3 + y * -3) = 2(y + -5) + -11
2y + (12 + -3y) = 2(y + -5) + -11

Reorder the terms:
12 + 2y + -3y = 2(y + -5) + -11

Combine like terms: 2y + -3y = -1y
12 + -1y = 2(y + -5) + -11

Reorder the terms:
12 + -1y = 2(-5 + y) + -11
12 + -1y = (-5 * 2 + y * 2) + -11
12 + -1y = (-10 + 2y) + -11

Reorder the terms:
12 + -1y = -10 + -11 + 2y

Combine like terms: -10 + -11 = -21
12 + -1y = -21 + 2y

Solving
12 + -1y = -21 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
12 + -1y + -2y = -21 + 2y + -2y

Combine like terms: -1y + -2y = -3y
12 + -3y = -21 + 2y + -2y

Combine like terms: 2y + -2y = 0
12 + -3y = -21 + 0
12 + -3y = -21

Add '-12' to each side of the equation.
12 + -12 + -3y = -21 + -12

Combine like terms: 12 + -12 = 0
0 + -3y = -21 + -12
-3y = -21 + -12

Combine like terms: -21 + -12 = -33
-3y = -33

Divide each side by '-3'.
y = 11

Simplifying
y = 11

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