2y-3+3(y-4)-5(y-6)=

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Solution for 2y-3+3(y-4)-5(y-6)= equation:


Simplifying
2y + -3 + 3(y + -4) + -5(y + -6) = 0

Reorder the terms:
2y + -3 + 3(-4 + y) + -5(y + -6) = 0
2y + -3 + (-4 * 3 + y * 3) + -5(y + -6) = 0
2y + -3 + (-12 + 3y) + -5(y + -6) = 0

Reorder the terms:
2y + -3 + -12 + 3y + -5(-6 + y) = 0
2y + -3 + -12 + 3y + (-6 * -5 + y * -5) = 0
2y + -3 + -12 + 3y + (30 + -5y) = 0

Reorder the terms:
-3 + -12 + 30 + 2y + 3y + -5y = 0

Combine like terms: -3 + -12 = -15
-15 + 30 + 2y + 3y + -5y = 0

Combine like terms: -15 + 30 = 15
15 + 2y + 3y + -5y = 0

Combine like terms: 2y + 3y = 5y
15 + 5y + -5y = 0

Combine like terms: 5y + -5y = 0
15 + 0 = 0
15 = 0

Solving
15 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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