2y-3+5y+10=42

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Solution for 2y-3+5y+10=42 equation:



2y-3+5y+10=42
We move all terms to the left:
2y-3+5y+10-(42)=0
We add all the numbers together, and all the variables
7y-35=0
We move all terms containing y to the left, all other terms to the right
7y=35
y=35/7
y=5

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