2y-3-5(y-2)=32

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Solution for 2y-3-5(y-2)=32 equation: 



2y-3-5(y-2)=32

We move all terms to the left:

2y-3-5(y-2)-(32)=0

We add all the numbers together, and all the variables

2y-5(y-2)-35=0

We multiply parentheses

2y-5y+10-35=0

We add all the numbers together, and all the variables

-3y-25=0

We move all terms containing y to the left, all other terms to the right

-3y=25

y=25/-3

y=-8+1/3

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