2y-3/3y+2=2/3

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Solution for 2y-3/3y+2=2/3 equation: 



2y-3/3y+2=2/3

We move all terms to the left:

2y-3/3y+2-(2/3)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

2y-3/3y+2-(+2/3)=0

We get rid of parentheses

2y-3/3y+2-2/3=0

We calculate fractions


2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1

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