2y-32=-3(y-1)

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Solution for 2y-32=-3(y-1) equation: 



2y-32=-3(y-1)

We move all terms to the left:

2y-32-(-3(y-1))=0



We calculate terms in parentheses: -(-3(y-1)), so:

-3(y-1)

We multiply parentheses

-3y+3

Back to the equation:

-(-3y+3)



We get rid of parentheses

2y+3y-3-32=0

We add all the numbers together, and all the variables

5y-35=0

We move all terms containing y to the left, all other terms to the right

5y=35

y=35/5

y=7

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