2y-32=7(y-1)

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Solution for 2y-32=7(y-1) equation:



2y-32=7(y-1)
We move all terms to the left:
2y-32-(7(y-1))=0
We calculate terms in parentheses: -(7(y-1)), so:
7(y-1)
We multiply parentheses
7y-7
Back to the equation:
-(7y-7)
We get rid of parentheses
2y-7y+7-32=0
We add all the numbers together, and all the variables
-5y-25=0
We move all terms containing y to the left, all other terms to the right
-5y=25
y=25/-5
y=-5

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