2y-3=11y+42

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Solution for 2y-3=11y+42 equation: 



2y-3=11y+42

We move all terms to the left:

2y-3-(11y+42)=0

We get rid of parentheses

2y-11y-42-3=0

We add all the numbers together, and all the variables

-9y-45=0

We move all terms containing y to the left, all other terms to the right

-9y=45

y=45/-9

y=-5

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