2y-3=3y-2-2y

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Solution for 2y-3=3y-2-2y equation: 



2y-3=3y-2-2y

We move all terms to the left:

2y-3-(3y-2-2y)=0

We add all the numbers together, and all the variables

2y-(y-2)-3=0

We get rid of parentheses

2y-y+2-3=0

We add all the numbers together, and all the variables

y-1=0

We move all terms containing y to the left, all other terms to the right

y=1

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