2y-4(2y-1)=3(5y-3)-8

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Solution for 2y-4(2y-1)=3(5y-3)-8 equation: 



2y-4(2y-1)=3(5y-3)-8

We move all terms to the left:

2y-4(2y-1)-(3(5y-3)-8)=0

We multiply parentheses

2y-8y-(3(5y-3)-8)+4=0



We calculate terms in parentheses: -(3(5y-3)-8), so:

3(5y-3)-8

We multiply parentheses

15y-9-8

We add all the numbers together, and all the variables

15y-17

Back to the equation:

-(15y-17)



We add all the numbers together, and all the variables

-6y-(15y-17)+4=0

We get rid of parentheses

-6y-15y+17+4=0

We add all the numbers together, and all the variables

-21y+21=0

We move all terms containing y to the left, all other terms to the right

-21y=-21

y=-21/-21

y=1

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