2y-4(y+1)=-(5y+6)+y

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Solution for 2y-4(y+1)=-(5y+6)+y equation: 



2y-4(y+1)=-(5y+6)+y

We move all terms to the left:

2y-4(y+1)-(-(5y+6)+y)=0

We multiply parentheses

2y-4y-(-(5y+6)+y)-4=0



We calculate terms in parentheses: -(-(5y+6)+y), so:

-(5y+6)+y

We add all the numbers together, and all the variables

y-(5y+6)

We get rid of parentheses

y-5y-6

We add all the numbers together, and all the variables

-4y-6

Back to the equation:

-(-4y-6)



We add all the numbers together, and all the variables

-2y-(-4y-6)-4=0

We get rid of parentheses

-2y+4y+6-4=0

We add all the numbers together, and all the variables

2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1

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