2y-4=1/3(y+7)

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Solution for 2y-4=1/3(y+7) equation: 



2y-4=1/3(y+7)

We move all terms to the left:

2y-4-(1/3(y+7))=0



Domain of the equation: 3(y+7))!=0

y∈R



We multiply all the terms by the denominator


2y*3(y+7))-(1-4*3(y+7))=0

Wy multiply elements

6y^2(y-12y(y=0

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