2y-5(4y-4)=-2-3(2-y)

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Solution for 2y-5(4y-4)=-2-3(2-y) equation: 



2y-5(4y-4)=-2-3(2-y)

We move all terms to the left:

2y-5(4y-4)-(-2-3(2-y))=0

We add all the numbers together, and all the variables

2y-5(4y-4)-(-2-3(-1y+2))=0

We multiply parentheses

2y-20y-(-2-3(-1y+2))+20=0



We calculate terms in parentheses: -(-2-3(-1y+2)), so:

-2-3(-1y+2)

determiningTheFunctionDomain
-3(-1y+2)-2

We multiply parentheses

3y-6-2

We add all the numbers together, and all the variables

3y-8

Back to the equation:

-(3y-8)



We add all the numbers together, and all the variables

-18y-(3y-8)+20=0

We get rid of parentheses

-18y-3y+8+20=0

We add all the numbers together, and all the variables

-21y+28=0

We move all terms containing y to the left, all other terms to the right

-21y=-28

y=-28/-21

y=1+1/3

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