2y-5(y-4)=17

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Solution for 2y-5(y-4)=17 equation: 



2y-5(y-4)=17

We move all terms to the left:

2y-5(y-4)-(17)=0

We multiply parentheses

2y-5y+20-17=0

We add all the numbers together, and all the variables

-3y+3=0

We move all terms containing y to the left, all other terms to the right

-3y=-3

y=-3/-3

y=1

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