2y-5-6y=3(y+1)+1

Solution for 2y-5-6y=3(y+1)+1 equation:

2y-5-6y=3(y+1)+1

We move all terms to the left:

2y-5-6y-(3(y+1)+1)=0

We add all the numbers together, and all the variables

-4y-(3(y+1)+1)-5=0


We calculate terms in parentheses: -(3(y+1)+1), so:

3(y+1)+1

We multiply parentheses

3y+3+1

We add all the numbers together, and all the variables

3y+4

Back to the equation:

-(3y+4)


We get rid of parentheses

-4y-3y-4-5=0

We add all the numbers together, and all the variables

-7y-9=0

We move all terms containing y to the left, all other terms to the right

-7y=9

y=9/-7

y=-1+2/7