2y-6+13=-(4y-2)+10

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Solution for 2y-6+13=-(4y-2)+10 equation: 



2y-6+13=-(4y-2)+10

We move all terms to the left:

2y-6+13-(-(4y-2)+10)=0

We add all the numbers together, and all the variables

2y-(-(4y-2)+10)+7=0



We calculate terms in parentheses: -(-(4y-2)+10), so:

-(4y-2)+10

We get rid of parentheses

-4y+2+10

We add all the numbers together, and all the variables

-4y+12

Back to the equation:

-(-4y+12)



We get rid of parentheses

2y+4y-12+7=0

We add all the numbers together, and all the variables

6y-5=0

We move all terms containing y to the left, all other terms to the right

6y=5

y=5/6

y=5/6

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