2y-6+2(6y+8)=-4(y+1)

Solution for 2y-6+2(6y+8)=-4(y+1) equation:

2y-6+2(6y+8)=-4(y+1)

We move all terms to the left:

2y-6+2(6y+8)-(-4(y+1))=0

We multiply parentheses

2y+12y-(-4(y+1))+16-6=0


We calculate terms in parentheses: -(-4(y+1)), so:

-4(y+1)

We multiply parentheses

-4y-4

Back to the equation:

-(-4y-4)


We add all the numbers together, and all the variables

14y-(-4y-4)+10=0

We get rid of parentheses

14y+4y+4+10=0

We add all the numbers together, and all the variables

18y+14=0

We move all terms containing y to the left, all other terms to the right

18y=-14

y=-14/18

y=-7/9