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2y-6=5(y-1)-(3y-4)
We move all terms to the left:
2y-6-(5(y-1)-(3y-4))=0
We calculate terms in parentheses: -(5(y-1)-(3y-4)), so:We get rid of parentheses
5(y-1)-(3y-4)
We multiply parentheses
5y-(3y-4)-5
We get rid of parentheses
5y-3y+4-5
We add all the numbers together, and all the variables
2y-1
Back to the equation:
-(2y-1)
2y-2y+1-6=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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