2y-7+4y=3(2y-1)-4

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Solution for 2y-7+4y=3(2y-1)-4 equation: 



2y-7+4y=3(2y-1)-4

We move all terms to the left:

2y-7+4y-(3(2y-1)-4)=0

We add all the numbers together, and all the variables

6y-(3(2y-1)-4)-7=0



We calculate terms in parentheses: -(3(2y-1)-4), so:

3(2y-1)-4

We multiply parentheses

6y-3-4

We add all the numbers together, and all the variables

6y-7

Back to the equation:

-(6y-7)



We get rid of parentheses

6y-6y+7-7=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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