2y-7+5(2y+1)=-6(y+3)

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Solution for 2y-7+5(2y+1)=-6(y+3) equation: 



2y-7+5(2y+1)=-6(y+3)

We move all terms to the left:

2y-7+5(2y+1)-(-6(y+3))=0

We multiply parentheses

2y+10y-(-6(y+3))+5-7=0



We calculate terms in parentheses: -(-6(y+3)), so:

-6(y+3)

We multiply parentheses

-6y-18

Back to the equation:

-(-6y-18)



We add all the numbers together, and all the variables

12y-(-6y-18)-2=0

We get rid of parentheses

12y+6y+18-2=0

We add all the numbers together, and all the variables

18y+16=0

We move all terms containing y to the left, all other terms to the right

18y=-16

y=-16/18

y=-8/9

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