2y-7+7(2y+3)=-2(y+1)

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Solution for 2y-7+7(2y+3)=-2(y+1) equation: 



2y-7+7(2y+3)=-2(y+1)

We move all terms to the left:

2y-7+7(2y+3)-(-2(y+1))=0

We multiply parentheses

2y+14y-(-2(y+1))+21-7=0



We calculate terms in parentheses: -(-2(y+1)), so:

-2(y+1)

We multiply parentheses

-2y-2

Back to the equation:

-(-2y-2)



We add all the numbers together, and all the variables

16y-(-2y-2)+14=0

We get rid of parentheses

16y+2y+2+14=0

We add all the numbers together, and all the variables

18y+16=0

We move all terms containing y to the left, all other terms to the right

18y=-16

y=-16/18

y=-8/9

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