2y-8+2(2y+5)=-2(y+8)

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Solution for 2y-8+2(2y+5)=-2(y+8) equation: 



2y-8+2(2y+5)=-2(y+8)

We move all terms to the left:

2y-8+2(2y+5)-(-2(y+8))=0

We multiply parentheses

2y+4y-(-2(y+8))+10-8=0



We calculate terms in parentheses: -(-2(y+8)), so:

-2(y+8)

We multiply parentheses

-2y-16

Back to the equation:

-(-2y-16)



We add all the numbers together, and all the variables

6y-(-2y-16)+2=0

We get rid of parentheses

6y+2y+16+2=0

We add all the numbers together, and all the variables

8y+18=0

We move all terms containing y to the left, all other terms to the right

8y=-18

y=-18/8

y=-2+1/4

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