2y-8+3(2y+4)=-2(y+5)

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Solution for 2y-8+3(2y+4)=-2(y+5) equation: 



2y-8+3(2y+4)=-2(y+5)

We move all terms to the left:

2y-8+3(2y+4)-(-2(y+5))=0

We multiply parentheses

2y+6y-(-2(y+5))+12-8=0



We calculate terms in parentheses: -(-2(y+5)), so:

-2(y+5)

We multiply parentheses

-2y-10

Back to the equation:

-(-2y-10)



We add all the numbers together, and all the variables

8y-(-2y-10)+4=0

We get rid of parentheses

8y+2y+10+4=0

We add all the numbers together, and all the variables

10y+14=0

We move all terms containing y to the left, all other terms to the right

10y=-14

y=-14/10

y=-1+2/5

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