2y-8+4(3y+1)=-2(y+1)

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Solution for 2y-8+4(3y+1)=-2(y+1) equation: 



2y-8+4(3y+1)=-2(y+1)

We move all terms to the left:

2y-8+4(3y+1)-(-2(y+1))=0

We multiply parentheses

2y+12y-(-2(y+1))+4-8=0



We calculate terms in parentheses: -(-2(y+1)), so:

-2(y+1)

We multiply parentheses

-2y-2

Back to the equation:

-(-2y-2)



We add all the numbers together, and all the variables

14y-(-2y-2)-4=0

We get rid of parentheses

14y+2y+2-4=0

We add all the numbers together, and all the variables

16y-2=0

We move all terms containing y to the left, all other terms to the right

16y=2

y=2/16

y=1/8

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