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2y-8=1/2(2-5y)
We move all terms to the left:
2y-8-(1/2(2-5y))=0
Domain of the equation: 2(2-5y))!=0We add all the numbers together, and all the variables
y∈R
2y-(1/2(-5y+2))-8=0
We multiply all the terms by the denominator
2y*2(-5y+2))-(1-8*2(-5y+2))=0
Wy multiply elements
4y^2(--16y(-=0
We use the square of the difference formula
4y^2(+16y(-=0
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