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2y-8y=10y(2)=20
We move all terms to the left:
2y-8y-(10y(2))=0
determiningTheFunctionDomain 2y-8y-10y2=0
We add all the numbers together, and all the variables
-10y^2-6y=0
a = -10; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·(-10)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*-10}=\frac{0}{-20} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*-10}=\frac{12}{-20} =-3/5 $
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