2y/(y-8)+2=8y/(y-8)

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Solution for 2y/(y-8)+2=8y/(y-8) equation: 


D( y )

y-8 = 0

y-8 = 0

y-8 = 0

y-8 = 0 // + 8

y = 8

y in (-oo:8) U (8:+oo)

(2*y)/(y-8)+2 = (8*y)/(y-8) // - (8*y)/(y-8)

(2*y)/(y-8)-((8*y)/(y-8))+2 = 0

(2*y)/(y-8)-8*y*(y-8)^-1+2 = 0

(2*y)/(y-8)+(-8*y)/(y-8)+2 = 0

(2*y)/(y-8)+(-8*y)/(y-8)+(2*(y-8))/(y-8) = 0

2*(y-8)+2*y-8*y = 0

2*y-6*y-16 = 0

-4*y-16 = 0

(-4*y-16)/(y-8) = 0

(-4*y-16)/(y-8) = 0 // * y-8

-4*y-16 = 0

-4*y-16 = 0 // + 16

-4*y = 16 // : -4

y = 16/(-4)

y = -4

y = -4

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