2y/2y-3+3/3-2y

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Solution for 2y/2y-3+3/3-2y equation: 


y in (-oo:+oo)

((2*y)/2)*y-(2*y)+3/3-3 = 0

((2*y)/2)*y-2*y+3/3-3 = 0

y^2-2*y-2 = 0

DELTA = (-2)^2-(-2*1*4)

DELTA = 12

DELTA > 0

y = (12^(1/2)+2)/(1*2) or y = (2-12^(1/2))/(1*2)

y = (2*3^(1/2)+2)/2 or y = (2-2*3^(1/2))/2

y in { (2-2*3^(1/2))/2, (2*3^(1/2)+2)/2 }

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