2y/4=32/y

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Solution for 2y/4=32/y equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(2*y)/4 = 32/y // - 32/y

(2*y)/4-(32/y) = 0

(2*y)/4-32*y^-1 = 0

1/2*y^1-32*y^-1 = 0

(1/2*y^2-32*y^0)/(y^1) = 0 // * y^2

y^1*(1/2*y^2-32*y^0) = 0

y^1

(1/2)*y^2-32 = 0

(1/2)*y^2-32 = 0

DELTA = 0^2-(-32*4*(1/2))

DELTA = 64

DELTA > 0

y = (64^(1/2)+0)/(2*(1/2)) or y = (0-64^(1/2))/(2*(1/2))

y = 8 or y = -8

y in { -8, 8}

y in { -8, 8 }

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