2y/9=8/y

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Solution for 2y/9=8/y equation:


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(2*y)/9 = 8/y // - 8/y

(2*y)/9-(8/y) = 0

(2*y)/9-8*y^-1 = 0

2/9*y^1-8*y^-1 = 0

(2/9*y^2-8*y^0)/(y^1) = 0 // * y^2

y^1*(2/9*y^2-8*y^0) = 0

y^1

(2/9)*y^2-8 = 0

(2/9)*y^2-8 = 0

DELTA = 0^2-(-8*4*(2/9))

DELTA = 64/9

DELTA > 0

y = ((64/9)^(1/2)+0)/(2*(2/9)) or y = (0-(64/9)^(1/2))/(2*(2/9))

y = 6 or y = -6

y in { -6, 6}

y in { -6, 6 }

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