2y/y-8+1=7y/y-8

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Solution for 2y/y-8+1=7y/y-8 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(2*y)/y-8+1 = (7*y)/y-8 // - (7*y)/y-8

(2*y)/y-((7*y)/y)-8+1+8 = 0

(2*y)/y-8-7+1+8 = 0

-4 = 0

y belongs to the empty set

y belongs to the empty set

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