2y2+11y=y2+3y-28

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Solution for 2y2+11y=y2+3y-28 equation: 



2y^2+11y=y2+3y-28

We move all terms to the left:

2y^2+11y-(y2+3y-28)=0

We add all the numbers together, and all the variables

2y^2-(+y^2+3y-28)+11y=0

We get rid of parentheses

2y^2-y^2-3y+11y+28=0

We add all the numbers together, and all the variables

y^2+8y+28=0

a = 1; b = 8; c = +28;
Δ = b2-4ac
Δ = 82-4·1·28
Δ = -48
Delta is less than zero, so there is no solution for the equation

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