2y2+13y+15=0

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Solution for 2y2+13y+15=0 equation:



2y^2+13y+15=0
a = 2; b = 13; c = +15;
Δ = b2-4ac
Δ = 132-4·2·15
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-7}{2*2}=\frac{-20}{4} =-5 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+7}{2*2}=\frac{-6}{4} =-1+1/2 $

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