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2y^2+33y-17=0
a = 2; b = 33; c = -17;
Δ = b2-4ac
Δ = 332-4·2·(-17)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-35}{2*2}=\frac{-68}{4} =-17 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+35}{2*2}=\frac{2}{4} =1/2 $
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