2y2+34y+144=0

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Solution for 2y2+34y+144=0 equation: 



2y^2+34y+144=0

a = 2; b = 34; c = +144;
Δ = b2-4ac
Δ = 342-4·2·144
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-2}{2*2}=\frac{-36}{4}
=-9
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+2}{2*2}=\frac{-32}{4}
=-8
$

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