2y2+4y-70=0

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Solution for 2y2+4y-70=0 equation: 



2y^2+4y-70=0

a = 2; b = 4; c = -70;
Δ = b2-4ac
Δ = 42-4·2·(-70)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-24}{2*2}=\frac{-28}{4}
=-7
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+24}{2*2}=\frac{20}{4}
=5
$

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