If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2y^2-1=149
We move all terms to the left:
2y^2-1-(149)=0
We add all the numbers together, and all the variables
2y^2-150=0
a = 2; b = 0; c = -150;
Δ = b2-4ac
Δ = 02-4·2·(-150)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*2}=\frac{0-20\sqrt{3}}{4} =-\frac{20\sqrt{3}}{4} =-5\sqrt{3} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*2}=\frac{0+20\sqrt{3}}{4} =\frac{20\sqrt{3}}{4} =5\sqrt{3} $
| 4(x+4)=5(x+3) | | X+3=2x/6+2 | | 2x–7=8 | | 2x(x^2-14x+40)=0 | | 7x-21=-2x-3 | | 4(3x-5)=-9x+4 | | q=123 | | 33x-84=6 | | w=91 | | 4/9=46/(r+3) | | 3(5q-3)=2(4q+4) | | 3x=-42-11x | | (z-4)/3=27/8 | | -5(-2x-1)=-7x+6 | | 8x+6-10x+7=7 | | -12e=9 | | 6(a-4)=-30 | | (x)(12-2x)(8-2x)=200 | | (x)(12-2x)(20-2x)=55 | | (x-1)(x)=(x+4)(3) | | 0.4x+8=5.4x-12 | | P(x)=5(x^2+1)+16 | | -3(5x-1)=-19x-4 | | 1/2(x+34.65)=37.8 | | 0.6x−4.8+3x−1.2x+8.4=x | | 3n^2-19n-40=0 | | 5(x-4)=6(x-5) | | 3n^2-19n-240=0 | | 36x=-36-9 | | -x2+6x-1=0 | | -4x-1+3x=-5x-7 | | 12z^2-4=8z |