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2y^2-24y+64=0
a = 2; b = -24; c = +64;
Δ = b2-4ac
Δ = -242-4·2·64
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8}{2*2}=\frac{16}{4} =4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8}{2*2}=\frac{32}{4} =8 $
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