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2y^2-37y+161=0
a = 2; b = -37; c = +161;
Δ = b2-4ac
Δ = -372-4·2·161
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-9}{2*2}=\frac{28}{4} =7 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+9}{2*2}=\frac{46}{4} =11+1/2 $
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