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2y^2-92y+960=0
a = 2; b = -92; c = +960;
Δ = b2-4ac
Δ = -922-4·2·960
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-92)-28}{2*2}=\frac{64}{4} =16 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-92)+28}{2*2}=\frac{120}{4} =30 $
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