2y2/3=18

Solution for 2y2/3=18 equation:

2y^2/3=18

We move all terms to the left:

2y^2/3-(18)=0

We multiply all the terms by the denominator


2y^2-18*3=0

We add all the numbers together, and all the variables

2y^2-54=0

a = 2; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·2·(-54)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*2}=\frac{0-12\sqrt{3}}{4}
=-\frac{12\sqrt{3}}{4}
=-3\sqrt{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*2}=\frac{0+12\sqrt{3}}{4}
=\frac{12\sqrt{3}}{4}
=3\sqrt{3}
$