2y2=+3y-y+14y2

Solution for 2y2=+3y-y+14y2 equation:

2y^2=+3y-y+14y^2

We move all terms to the left:

2y^2-(+3y-y+14y^2)=0

We get rid of parentheses

2y^2-14y^2-3y+y=0

We add all the numbers together, and all the variables

-12y^2-2y=0

a = -12; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-12)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-12}=\frac{0}{-24}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-12}=\frac{4}{-24}
=-1/6
$