2y=(2/5)y+3

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Solution for 2y=(2/5)y+3 equation: 



2y=(2/5)y+3

We move all terms to the left:

2y-((2/5)y+3)=0



Domain of the equation: 5)y+3)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

2y-((+2/5)y+3)=0

We multiply all the terms by the denominator


2y*5)y+3)-((+2=0

Wy multiply elements

10y^2+2=0

a = 10; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·10·2
Δ = -80
Delta is less than zero, so there is no solution for the equation

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