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2y=1/5y+9
We move all terms to the left:
2y-(1/5y+9)=0
Domain of the equation: 5y+9)!=0We get rid of parentheses
y∈R
2y-1/5y-9=0
We multiply all the terms by the denominator
2y*5y-9*5y-1=0
Wy multiply elements
10y^2-45y-1=0
a = 10; b = -45; c = -1;
Δ = b2-4ac
Δ = -452-4·10·(-1)
Δ = 2065
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2065}}{2*10}=\frac{45-\sqrt{2065}}{20} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2065}}{2*10}=\frac{45+\sqrt{2065}}{20} $
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