2y=10(4+0.2y)-8

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Solution for 2y=10(4+0.2y)-8 equation: 



2y=10(4+0.2y)-8

We move all terms to the left:

2y-(10(4+0.2y)-8)=0

We add all the numbers together, and all the variables

2y-(10(0.2y+4)-8)=0



We calculate terms in parentheses: -(10(0.2y+4)-8), so:

10(0.2y+4)-8

We multiply parentheses

0y+40-8

We add all the numbers together, and all the variables

y+32

Back to the equation:

-(y+32)



We get rid of parentheses

2y-y-32=0

We add all the numbers together, and all the variables

y-32=0

We move all terms containing y to the left, all other terms to the right

y=32

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